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数学物理学报, 2021, 41(5): 1357-1371 doi:

论文

一类k-Hessian方程解的存在性和渐近稳定性

张丽红,1, 杨泽栋,1, 王国涛,1,2

1 山西师范大学数学与计算机科学学院 山西临汾 041004

2 Nonlinear Analysis and Applied Mathematics (NAAM) Research Group, Department of Mathematics, Faculty of Science, King Abdulaziz University, Saudi Arabia Jeddah 21589

3 Department of Mathematics, Faculty of Art and Sciences, Cankaya University, Turkey, Ankara Balgat 06530

4 Institute of Space Sciences, Magurele-Bucharest, Romania

Existence and Asymptotic Behavior of Solutions of a Class of k-Hessian Equation

Zhang Lihong,1, Yang Zedong,1, Wang Guotao,1,2, Baleanu Dumitru,3,4

1 School of Mathematics and Computer Science, Shanxi Normal University, Shanxi Linfen 041004

通讯作者: 王国涛, E-mail: wgt2512@163.com

收稿日期: 2020-11-7  

基金资助: 国家自然科学基金.  11501342
国家自然科学基金.  12001344
山西省研究生教育创新项目基金.  2020SY337

Received: 2020-11-7  

Fund supported: the NSFC.  11501342
the NSFC.  12001344
the Graduate Education Innovation Program Fund of Shanxi.  2020SY337

作者简介 About authors

张丽红,E-mail:zhanglih149@126.com , E-mail:zhanglih149@126.com

杨泽栋,E-mail:yangzd1229@163.com , E-mail:yangzd1229@163.com

BaleanuDumitru,E-mail:dumitru@cankaya.edu.tr , E-mail:dumitru@cankaya.edu.tr

Abstract

In this paper, we consider the following boundary blow-up k-Hessian problem

Sk(λ(D2z))=b(x)f(z),  xΩ,  zΩ=+,
where ΩRN is a smooth, bounded, strictly convex domain. We are concerned with the existence of the radially symmetric positive solutions of the k-Hessian equation and obtain new boundary asymptotic behavior of strictly convex blow-up positive solutions of the k-Hessian equation. Our approach mainly relies on the monotone iterative method, the upper and lower solution method and Karamata regular variation theory.

Keywords: Asymptotic behavior ; k-Hessian equation ; Positive radial solution ; Keller-Osserman condition ; Karamata regular variation theory

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本文引用格式

张丽红, 杨泽栋, 王国涛. 一类k-Hessian方程解的存在性和渐近稳定性. 数学物理学报[J], 2021, 41(5): 1357-1371 doi:

Zhang Lihong, Yang Zedong, Wang Guotao, Baleanu Dumitru. Existence and Asymptotic Behavior of Solutions of a Class of k-Hessian Equation. Acta Mathematica Scientia[J], 2021, 41(5): 1357-1371 doi:

1 引言

该文研究以下k-Hessian问题的k凸径向正解的存在性和边界渐近行为

{Sk(λ(D2z))=b(x)f(z), in Ω,z=+, on Ω,
(1.1)

其中, ΩRN(N2)是一个严格凸的光滑有界区域, 方程(1.1) 中的条件表示当d(x)=dist(x,Ω)0时, z(x)+.Ω=BR, 其中, BRRN是以原点为心半径为R>0的球, 则方程(1.1) 的条件应替换为z(x)+,(xR).BR上, 方程(1.1) 满足z(x)+,(xR)的解被称为爆破解. 特别地, 若Ω=RN, 则解被称为整体爆破解.

Sk(λ(D2z))k-Hessian算子形式如下

Sk(λ(D2z))=1j1<<jkNλj1λj2λjk,k=1,2,,N,

其中, D2z=(2zxixj)zC2(RN)的Hessian矩阵, λ(D2z)=(λ1,λ2,,λN)是Hessian矩阵D2z的特征值构成的向量, λ1,λ2,,λN是Hessian矩阵D2z的特征值.

令锥Γk{λRN:Sk(λ(D2z))>0}RN且含正锥

Γ+={λRN:λi>0,i=1,2,,N},

则由文献[1] 和[2]可知

Γ+=ΓNΓk+1ΓkΓ1.

定义 1.1[3]   令ΩRN的有界开子集且k{1,2,,N}. 若对于xΩ, (λ1,λ2,,λN)¯Γk, 则函数zC2(Ω)k凸. 换句话说, 若在Ω中, Si(λ(D2z))0(i=1,2,k), 则函数zC2(Ω)k凸.

定义 1.2[3]   令ΩRN是具有C2边界的开集且k{1,2,,N1}. 若对于ˉxΩ, Si(κj(ˉx),,κN1(ˉx))>0(i=1,2,,k), 则Ω是严格凸的. 其中, κj(ˉx)(j=1,2,,N1)Ω关于ˉx的主曲率.

Sk(λ(D2z))是一个包含诸多著名算子的集合. 当k=1时, k-Hessian算子是Laplace算子; 当k=N时, k-Hessian算子是Monge-Ampère算子, 即

  

Laplace算子Monge-Ampère算子
S1(λ(D2z(x)))=Ni=1λi=Δz,SN(λ(D2z(x)))=Ni=1λi=detD2z.

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近年来, Laplace问题和Monge-Ampère问题被广泛应用于数学和应用数学的诸多分支. 关于Monge-Ampère问题和Laplace问题解的存在性、非存在性、多解性、唯一性和渐近稳定性结果见文献[4-17]. 例如, 在2015年, 应用Karamata正则变化理论(其被Karamata于1930年建立, 是研究随机过程[18-20]和非线性椭圆问题解的渐近稳定性的一个有用的工具), 张[4]研究了下列边界爆破Monge-Ampère问题严格凸解的边界行为

{detD2z=b(x)f(z), in Ω,z=+, on Ω,
(1.2)

其中, ΩRN是一个严格凸的光滑有界区域.

在2019年, 应用Karamata正则变化理论, Khamessi和Othman[6]研究了下列奇异Laplace问题正解的边界渐近行为

{z=b(x)f(z), in Ω,z>0, in Ω,z=+, on Ω,
(1.3)

其中, ΩRN是一个严格凸的光滑有界区域.

在2019年, 应用单调迭代方法, Covei[7]分别研究了下列Laplace方程整体有界径向解和爆破径向解的存在性

z=b(|x|)f(z)+h(|x|)g(z),xRN,
(1.4)

在方程(1.4) 中, 当f(z)=zα, g(z)=zβ, 0<αβ时, Lair[8]研究了整体爆破径向正解的存在性和非存在性.

在2012年, Dupaigne等[9]分别得到了下列半线性椭圆方程整体有界解和爆破解的存在性, 并且研究了解的唯一性、对称性和渐近稳定性

z=b(|x|)f(z),xRN.
(1.5)

在问题(1.1) 中, 当k=1时, 这些问题源于现实世界的许多现象. 例如, 生产规划问题相应的标量情况模型[21]. 当k2时, k-Hessian方程是完全非线性偏微分方程. 在流体力学、几何问题和其它应用学科中, 它有着重要的应用. 例如, 在文献[17]中, k-Hessian问题可以描述反射器的形状设计或Weingarten曲率. 近年来, 诸多学者对k-Hessian问题产生了浓厚的研究兴趣, 并且应用诸如单调迭代方法、上下解方法、不动点定理、变分法、移动平面法和Perron's方法等方法得到了很多关于k-Hessian问题的优秀成果, 参见文献[22-34].

在2015年, 应用Arzela-Ascoli定理和单调迭代方法, 张和周[22]分别得到了k-Hessian方程

Sk(λ(D2z))=b(|x|)f(z),xRN
(1.6)

和Hessian方程组

{Sk(λ(D2z1))=b(|x|)f(z2),xRN,Sk(λ(D2z2))=h(|x|)g(z1),xRN
(1.7)

径向解的有界性和爆破性.

在2017年, 应用Perron's方法, 曹和保[34]研究了Hessian方程Dirichlet问题粘性解的存在性和唯一性

Sk(λ(D2z))=f(x),xRN¯Ω,
(1.8)

其中, ΩRN(N3)是一个光滑有界区域.

在2019年, 应用上下解方法, 马和李[26]研究了k-Hessian方程(1.1) 粘性解的存在性和渐近稳定性. 这里, f满足Keller-Osserman型条件

t1((k+1)F1(s))1k+1ds<,t>0,
(1.9)

其中, F1(s)=s0f(τ)dτ.

在2020年, 应用上下解方法, 冯和张[27]得到了下列边界爆破问题k凸径向解的存在性与非存在性

Sk(λ(D2z))=b(x)[z(x)]k[lnz(x)]β,xΩ,zΩ=+,
(1.10)

其中, β>0.

受文献[15] 的启发, 本文首先利用单调迭代方法, 分别在球BR和全空间RN上, 研究了k-Hessian方程(1.1) 严格凸的径向对称正解的存在性. 然后应用上下解方法和Karamata正则变化理论, 在严格凸的光滑有界区域Ω上, 得到了k-Hessian方程(1.1) 严格凸的爆破解的边界渐近行为. 关于单调迭代方法和上下解方法在研究非线性问题方面的作用, 请参见文献[22-27, 35-43]. 我们的主要结果改进和扩展了以前的工作, 请参见文献[1, 3-4, 9, 15-16, 22, 26].

2 预备知识

该节给出一些预备知识和关于Karamata正则变化理论的著名结果. 记ψ

ψ(t)ds(kf(s))1k=t,t>0
(2.1)

的唯一解. 设f满足

(S1)   fC1[0,)是一个严格单调递增的函数且f(0)=0;

(S2)   sdtF(t)<, F(s):=(kf(s))1k, s>0;

(S3)   存在一个正常数C+f使得

lim

其中, J_{f}(s): = F^{\prime}(s) \int_{s}^{\infty} \frac{{\rm d}t}{F(t)}, s>0 .

注 2.1  (1) 若 (S_{1}) (S_{2}) 成立, 则 f 满足Keller-Osserman型条件[1, 3-4, 16, 26] (1.9) 式. 详细的证明请参看文献[15];

(2) 由 (S_{1}) , (S_{2}) (S_{3}) 可知 \psi(t) \rightarrow +\infty \Leftrightarrow t \rightarrow 0.

b 满足

(B_{1})    在 \Omega 中, b \in C^{\infty}(\Omega) 是一个正函数.

(B_{2})    b 是一个球对称连续函数, 即, 对于 r = |x| , b(x) = b(r) .

(B_{3})    存在 g \in \Lambda 和正常数 b_{i} (i = 1, 2) 使得

b_{1}: = \lim\limits _{d(x) \rightarrow 0} \inf \frac{b(x)}{g^{k+1}(d(x))} \leq b_{2}: = \lim\limits _{d(x) \rightarrow 0} \sup \frac{b(x)}{g^{k+1}(d(x))},

其中, \Lambda 是一个所有单调正函数 g \in C^{1}(0, \delta_{0}) \bigcap L^{1}(0, \delta_{0}) (\delta_{0} > 0) 的集合且 g 满足

\begin{equation} \lim\limits _{t \rightarrow 0^{+}} \frac{\rm d}{{\rm d}t}\left(\frac{G(t)}{g(t)}\right): = G_{g} \in[0, \infty), \quad G(t): = \int_{0}^{t} g(v) {\rm d}v. \end{equation}
(2.2)

注 2.2[15]   关于 g \in \Lambda 的一些函数列举如下:

(1) 对于 \mu > 0 , 当 g(t) = \exp(-\frac{1}{t^{\mu}}) , t \in (0, \delta_{0}) 时, G_{g} = 0 ;

(2) 对于 \mu > 0 , 当 g(t) = t^{\mu} , t \in (0, \delta_{0}) 时, G(t) = \frac{t^{1+\mu}}{1+\mu} , G_{g} = \frac{1}{1+\mu} ;

(3) 对于 \mu > 0 , 当 g(t) = \frac{1}{(-\ln t)^{\mu}} , t \in (0, 1) 时, G_{g} = 1 ;

(4) 对于 \mu > 0 , 当 g(t) = \frac{1}{t^{\mu}} , t \in (0, \delta_{0}) 时, G(t) = \frac{t^{1-\mu}}{1-\mu} , G_{g} = \frac{1}{1-\mu} .

关于 g \in \Lambda 的一些性质列举如下.

引理 2.1[4]   如果 g \in \Lambda , 那么

(1) \lim\limits _{t \rightarrow 0^{+}} \frac{G(t)}{g(t)} = 0 ;

(2) \lim\limits _{t \rightarrow 0^{+}} \frac{G(t)g^{\prime}(t)}{g^{2}(t)} = 1-\lim\limits _{t \rightarrow 0^{+}} \frac{\rm d}{{\rm d}t}\left(\frac{G(t)}{g(t)}\right) = 1-G_{g} ;

(3) 若 G_{g} = 0 , 则 g 0 处比 t^{p} 增长的快, 其中, p > 1 ;

(4) 若 G_{g}>0 , 则 g 0 处是一个指数为 \frac{1-G_{g}}{G_{g}} 的标准正则变化函数. 特别地, 若 G_{g} = 1 , 则 g 0 处是一个标准慢变函数.

为了研究满足条件 (S_{2}) 和条件 (S_{3}) f 以及(2.1) 式中 \psi 的性质, 接下来, 引入关于Karamata正则变化理论的结果.

定义 2.1[44]   如果对于 \beta > 0 和某个 q \in {{\Bbb R}} , 正函数 f \in C^{1}[\zeta, \infty) , \zeta > 0 , 满足

\begin{equation} \lim \limits_{s \rightarrow \infty} \frac{f(\beta s)}{f(s)} = \beta^{q}. \end{equation}
(2.3)

那么 f 在无穷远处是一个指数为 q 的正则变化函数, 记 f \in RV_{q} . 特别地, 若 q = 0 , 则 f 在无穷远处是一个慢变函数.

显然, 当 f \in RV_{q} 时, L(s) : = \frac{f(s)}{s^{q}} 在无穷远处是慢变函数.

注 2.3  关于在无穷远处慢变函数的一些基本例子如下

(1) 每一个 f(s) \in C[\zeta, \infty) 在无穷远处有正极限;

(2) f(s) = \exp((\ln s)^{\mu}) , \mu \in (0, 1) ;

(3) f(s) = (\ln(\ln s))^{\mu} , \mu \in {{\Bbb R}} ;

(4) f(s) = (\ln s)^{\mu} , \mu \in {{\Bbb R}} .

命题 2.1[44](一致收敛定理)   当 f \in RV_{q} 时, 对于 \beta \in [\beta_{1}, \beta_{2}] 0 < \beta_{1} < \beta_{2} , (2.3)式一致成立.

命题 2.2[44](Karamata表达式定理)   H 在无穷远处是一个慢变函数当且仅当它可表示为以下形式

\begin{equation} H(s) = z(s)\exp\left(\int_{\zeta_{1}}^{s} \frac{y(\tau)}{\tau}{\rm d}\tau \right), \quad s \geq \zeta_{1}, \end{equation}
(2.4)

其中, \zeta_{1} \geq \zeta , z y 是连续的, \lim\limits _{s \rightarrow \infty}y(s) = 0 , \lim\limits _{s \rightarrow \infty}z(s) = c_{0} , c_{0} > 0 .

定义 2.2[44]   (1)

\begin{equation} \widetilde{H}(s) = c_{0} \exp\left(\int_{\zeta_{1}}^{s} \frac{y(\tau)}{\tau}{\rm d}\tau \right), \quad s \geq \zeta_{1}, \end{equation}
(2.5)

在无穷远处是一个标准慢变函数;

(2)

\begin{equation} f(s) = s^{q} \widetilde{H}(s), \quad s \geq \zeta_{1}, \end{equation}
(2.6)

在无穷远处是一个指数为 q 的标准正则变化函数(记 f \in NRV_{q} ).

等价地, f \in RV_{q} 属于 NRV_{q} 当且仅当对于 \zeta_{1} > 0 , f\in C^{1}[\zeta_{1}, \infty) 满足

\begin{equation} \lim\limits _{s \rightarrow \infty} \frac{sf'(s)}{f(s)} = q. \end{equation}
(2.7)

命题 2.3[44]   若 H , H_{1} 在无穷远处是慢变函数, 则

(1) H^{q} ( \forall q \in {{\Bbb R}} ), c_{1}H + c_{2}H_{1} , H \cdot H_{1} H \circ H_{1} ( \lim\limits _{s \rightarrow \infty} H_{1}(s) = \infty ) 在无穷远处是慢变函数, 其中, c_{1} \geq 0 , c_{2} \geq 0 , c_{1} + c_{2} > 0 ;

(2) \lim\limits _{s \rightarrow \infty} s^{q}H(s) \rightarrow \infty , \lim\limits _{s \rightarrow \infty} \frac{H(s)}{s^{q}} \rightarrow 0 , \forall q > 0 ;

(3) \lim\limits _{s \rightarrow \infty} \frac{\ln(H(s))}{\ln s} \rightarrow 0 , \lim\limits _{s \rightarrow \infty} \frac{\ln(s^{q} H(s))}{\ln s} \rightarrow q , \forall q \in {{\Bbb R}} .

命题 2.4[45](渐近行为)   若 H 在无穷远处是一个慢变函数, 则对于 a \geq 0 , 当 t \rightarrow \infty

(1) \int_{a}^{t} s^{q} H(s){\rm d}s\cong \frac{t^{q+1}}{q+1}, \quad q>-1 ;

(2) \int_{t}^{\infty} s^{q} H(s){\rm d}s\cong \frac{t^{q+1}}{-q-1}, \quad q<-1 .

类似地, 对于正函数 f \in C^{1}(-\infty, -\zeta) , \zeta > 0 (或 f \in C^{1}(0, s_{0}) , s_{0} > 0 ), 可给出在 -\infty 处(或在 0 处)标准正则变化(或正则变化) 的定义和一些基本性质.

引理 2.2[15]   假设 f 满足 (S_{1}) (S_{2}) , 那么

(1) 当 (S_{3}) 成立时, C^{+}_{f} \in [1, \infty) ;

(2) 当 (S_{3}) 成立时, 存在 T_{0} > 0 使得在 [T_{0}, \infty) \frac{f(s)}{s^{kl}} 是单调递增的, 其中, 对于 C^{+}_{f} > 1 , l \in \left(1, \frac{C^{+}_{f}}{C^{+}_{f} -1}\right) ; 对于 C^{+}_{f} = 1 , l \in (1, \infty) ;

(3) 对于 C^{+}_{f} >1 , (S_{3}) 成立当且仅当对于某个 p > 1 , f \in NRV_{kp} . 事实上, 这种情况下, p = \frac{C^{+}_{f}}{C^{+}_{f} -1} ;

(4) 对于 C^{+}_{f} = 1 , 当 (S_{3}) 成立时, 在无穷远处 s^{p} (p > k) f 增长的慢;

(5) 对于某个大的 T_{0} > 0 , 当 f \in C^{2}(T_{0}, \infty) \lim\limits _{s \rightarrow +\infty} \frac{f(s)f''(s)}{f'^{2}(s)} = 1 时, f 满足 (S_{3}) C^{+}_{f} = 1 .

\begin{equation} \Upsilon(s): = sF'(\psi(s)) = \frac{sf'(\psi(s))}{(kf(\psi(s)))^{(k-1)/k}}, \quad s>0. \end{equation}
(2.8)

引理 2.3[15]   假设 f 满足 (S_{1}) , (S_{2}) (S_{3}) , 那么

(1) \psi(s)>0 , s\in(0, \infty) , \psi(0): = \lim\limits_{s\rightarrow 0^{+}}\psi(s) = +\infty ;

(2) -\psi'(s) = F(\psi(s)) = \sqrt[k]{kf(\psi(s))}, \quad s\in(0, \infty) ;

(3) \psi''(s) = F(\psi(s))F'(\psi(s)) = \frac{f'(\psi(s))}{(kf(\psi(s)))^{(k-2)/k}}, \quad s\in(0, \infty) ;

(4) \lim\limits _{s \rightarrow 0^{+}} \frac{s \psi^{\prime}(s)}{\psi(s)} = -\lim\limits _{s \rightarrow 0^{+}} \frac{s F(\psi(s))}{\psi(s)} = -\lim\limits _{t \rightarrow +\infty} \frac{F(t) \int_{t}^{\infty} \frac{{\rm d}\tau}{F(\tau)}}{t} = -\left(C^{+}_{f}-1\right) ;

(5) \lim\limits _{s \rightarrow 0^{+}} \frac{s \psi^{\prime \prime}(s)}{\psi^{\prime}(s)} = -\lim\limits _{s \rightarrow 0^{+}} \frac{s f^{\prime}(\psi(s))}{(k f(\psi(s)))^{(k-1) / k}} = -\lim\limits _{t \rightarrow +\infty} F^{\prime}(t) \int_{t}^{\infty} \frac{{\rm d}\tau}{F(\tau)} = -C^{+}_{f} ;

(6) 对于 \beta \in [\beta_{1}, \beta_{2}] , 0 < \beta_{1} < \beta_{2} , \lim\limits _{s \rightarrow 0}\Upsilon(\beta s) = C^{+}_{f} 一致成立.

3 存在性

该节研究在球 B_{R} 和全空间 {{\Bbb R}} ^{N} k -Hessian方程(1.1)径向对称正解的存在性.

引理 3.1[46]   假设 y(r) \in C^{2}[0, R), \; y^{\prime}(0) = 0 . 那么, z(|x|) = y(r) \in C^{2}\left(B_{R}\right) , r = |x|<R , 并且

\begin{equation} \lambda\left(D^{2} z\right) = \left\{\begin{array}{ll} { } \left(y^{\prime \prime}(r), \frac{y^{\prime}(r)}{r}, \cdots , \frac{y^{\prime}(r)}{r}\right), \quad &r \in(0, R), \\ { } \left(y^{\prime \prime}(0), y^{\prime \prime}(0), \cdots , y^{\prime \prime}(0)\right), \quad& r = 0, \end{array}\right. \end{equation}
(3.1)

\begin{equation} S_{k}\left(\lambda\left(D^{2} z\right)\right) = \left\{\begin{array}{ll} { } C_{N-1}^{k-1} y^{\prime \prime}(r)\left(\frac{y^{\prime}(r)}{r}\right)^{k-1}+C_{N-1}^{k} \left(\frac{y^{\prime}(r)}{r}\right)^{k}, & r \in(0, R), \\ C_{N}^{k}\left(y^{\prime \prime}(0)\right)^{k}, \quad& r = 0, \end{array}\right. \end{equation}
(3.2)

其中 B_{R} = \left\{x \in {{\Bbb R}} ^{N} :|x|<R\right\} , C_{N}^{k} = \frac{N !}{k !(N-k) !} .

通过计算, 可以得到以下引理:

引理 3.2   令 \Omega = B_{R} , z(|x|) = y(r) k -Hessian方程(1.1) 的径向解当且仅当 y(r) 是以下常微分方程的解

\begin{equation} \left\{\frac{r^{N-k}}{k}\left[\left(y(r)\right)^{\prime}\right]^{k}\right\}^{\prime} = \frac{r^{N-1}}{C_{N-1}^{k-1}} b(r)f(y(r)), \quad r\in[0, R). \end{equation}
(3.3)

注 3.1  令 \Omega = B_{R} , 且 b \in C(B_{R}) 是正函数. 那么

\begin{equation} \int_{0}^{R} \left( \int_{0}^{t} b(s) {\rm d}s\right)^{\frac{1}{k}}{\rm d}t = \infty \end{equation}
(3.4)

当且仅当

\begin{equation} \int_{0}^{R}\left(\frac{k}{t^{N-k}} \int_{0}^{t} \frac{s^{N-1}}{C_{N-1}^{k-1}}b(s) {\rm d}s\right)^{\frac{1}{k}} {\rm d}t = \infty. \end{equation}
(3.5)

事实上, 由洛必达法则, 得

\lim\limits_{r\rightarrow R^{-}} \frac{ \int_{0}^{r} b(s) {\rm d}s}{\frac{k}{r^{N-k}} \int_{0}^{r} \frac{s^{N-1}}{C_{N-1}^{k-1}}b(s) {\rm d}s} = \frac{R^{1-k}C_{N-1}^{k-1}}{k}

\begin{eqnarray*} \lim\limits_{r\rightarrow R^{-}} \frac{\int_{0}^{r} \left(\int_{0}^{t} b(s) {\rm d}s\right)^{\frac{1}{k}}{\rm d}t}{\int_{0}^{r}\left(\frac{k}{t^{N-k}} \int_{0}^{t} \frac{s^{N-1}}{C_{N-1}^{k-1}}b(s) {\rm d}s\right)^{\frac{1}{k}} {\rm d}t} = \lim\limits_{r\rightarrow R^{-}} \frac{ \left(\int_{0}^{r} b(s) {\rm d}s\right)^{\frac{1}{k}}}{\left(\frac{k}{r^{N-k}} \int_{0}^{r} \frac{s^{N-1}}{C_{N-1}^{k-1}}b(s) {\rm d}s\right)^{\frac{1}{k}}} = \left(\frac{R^{1-k}C_{N-1}^{k-1}}{k}\right)^{\frac{1}{k}}. \end{eqnarray*}

由注3.1可知条件(3.4) 优于条件(3.5). 基于条件(3.4), 有以下两定理成立, 证明过程类似于文献[22] 中的定理1.1.

定理 3.1  令 \Omega = B_{R} . 假设

(1) f 满足 (S_{1})

\int_{1}^{\infty} \frac{{\rm d} s}{(f(s))^{\frac{1}{k}}} = \infty;

(2) b 满足 (B_{1}) , (B_{2})

\int_{0}^{R} \left(\int_{0}^{t} b(s) {\rm d}s\right)^{\frac{1}{k}}{\rm d}t = \infty.

则方程(1.1) 有无穷多严格凸的径向正解.

定理 3.2  令 \Omega = {{\Bbb R}} ^{N} . 假设

(1) f 满足 (S_{1})

\int_{1}^{\infty} \frac{{\rm d}s}{(f(s))^{\frac{1}{k}}} = \infty;

(2) b 满足 (B_{1}) , (B_{2})

\int_{0}^{\infty} \left(\int_{0}^{t} b(s) {\rm d}s\right)^{\frac{1}{k}}{\rm d}t = \infty.

则方程(1.1) 有无穷多严格凸的整体径向正解.

4 渐近稳定性

该节研究在严格凸的光滑有界区域 \Omega k -Hessian问题(1.1) 严格凸正解的渐近稳定性. 首先引入一些与 k -Hessian问题相关的引理.

引理 4.1[24](比较原理)   对 x \in \Omega z , 定义一个函数 f(x, z) , 其中, z 属于某个包含 z_{1} z_{2} 的区间, z_{1}, z_{2} \in C^{2}(\Omega)\bigcap C(\overline{\Omega}) , \Omega \subset {{\Bbb R}} ^{N} (N\geq2) 是一个有界区域. 若

(1) 对于 \forall x \in \Omega , f(x, z) 关于 z 是一个严格单调递增的函数;

(2) 在 \Omega 中, D^{2} z_{1} 是一个正定矩阵;

(3) S_{k}\left(\lambda\left(D^{2} z_{1}\right)\right)\geq f(x, z_{1}), \forall x \in \Omega ;

(4) S_{k}\left(\lambda\left(D^{2} z_{2}\right)\right)\leq f(x, z_{2}), \forall x \in \Omega ;

(5) z_{1}\leq z_{2}, \forall x \in \partial\Omega .

则在 \Omega 中, z_{1}\leq z_{2} .

引理 4.2[25]   令 z \in C^{2}(\Omega) 使得对于任意的 x \in \Omega , (z_{x_{i}x_{j}}) 的所有主子矩阵是可逆的. 设 h 是一个 C^{2} 函数, 那么

\begin{equation} S_{k}\left(\lambda\left(D^{2} h(z)\right)\right) = S_{k}\left(\lambda\left(D^{2} z\right)\right)\left[h^{\prime}(z)\right]^{k}+\left[h^{\prime}(z)\right]^{k-1} h^{\prime \prime}(z) \sum\limits_{i = 1}^{C_{N}^{k}} {\rm det} (z_{x_{is} x_{ij}})\left(\nabla z_{i}\right)^{T} B\left(z_{i}\right) \nabla z_{i}, \end{equation}
(4.1)

其中, A^{T} 是矩阵 A 的转置, B(z_{i}) i 阶主子矩阵 (z_{x_{is}x_{ij}}) 的逆, \det(z_{x_{is}x_{ij}}) (z_{x_{is}x_{ij}}) 的行列式,

\nabla z_{i} = \left(z_{x_{i 1}}, z_{x_{i 2}}, \cdots, z_{x_{i k}}\right)^{T}, i = 1, 2, \cdots , C_{N}^{k},

其中 C_{N}^{k} = \frac{N !}{k !(N-k) !} .

对于 \delta > 0 , 令

\Omega_{\delta} = \{x\in\Omega:0<d(x)<\delta\}.

\Omega C^{l} 光滑的且 l \geq 2 , 则由文献[47] 中的引理14.16和引理14.17可知存在 \delta_{1} \in (0, \delta_{0}) 使得 d \in C^{l}(\Omega_{\delta_{1}}) , 其中, \delta_{0} \Lambda 中已经被给定. 此外, 由文献[47] 中的引理14.17可知

\begin{equation} \left\{\begin{array}{l} D d(x) = (0, 0, \cdots , 1), \\ D^{2} d(x) = {\rm diag} \left[-\varepsilon_{1}, \cdots , -\varepsilon_{N-1}, 0\right], \end{array}\right. \end{equation}
(4.2)

其中, \varepsilon_{j} = \frac{\kappa_{j}\left(\bar{x}\right)}{1-\kappa_{j}\left(\bar{x}\right) d\left(x\right)} , \kappa_{j}(\bar{x}) (j = 1, 2, \cdots , N-1) \partial\Omega 关于 \bar{x} 的主曲率, \bar{x} 是点 x \in \Omega_{\delta_{1}} \partial\Omega 的投影.

引理 4.3[48]   若在 (0, \delta_{1}) 上, h 是一个 C^{2} 函数. 则, 对于 x \in \Omega_{\delta_{1}} , 有

\begin{eqnarray} S_{k}\left(\lambda\left(D^{2} h\left(d(x)\right)\right)\right) & = &\left[-h^{\prime}\left(d\left(x\right)\right)\right]^{k} S_{k}\left(\varepsilon_{1}, \cdots , \varepsilon_{N-1}\right){}\\ &&+\left[-h^{\prime}\left(d\left(x\right)\right)\right]^{k-1} h^{\prime \prime}\left(d\left(x\right)\right) S_{k-1}\left(\varepsilon_{1}, \cdots , \varepsilon_{N-1}\right). \end{eqnarray}
(4.3)

定理 4.1  令 f 满足 (S_{1}) , (S_{2}) (S_{3}) , b 满足 (B_{1}) (B_{3}) . 如果

\begin{equation} C^{+}_{f}>1, \end{equation}
(4.4)

\begin{equation} C^{+}_{f} = 1 \quad \mbox{ 且 } \quad G_{g}>0, \end{equation}
(4.5)

那么 k -Hessian问题(1.1) 的每一个严格凸解 z 满足

\begin{equation} 1 \leq \lim\limits_{d(x) \rightarrow 0} \inf \frac{z(x)}{\psi\left(\xi_{2} G^{\beta}(d(x))\right)} \quad \mbox{ 和 } \quad \lim\limits_{d(x) \rightarrow 0} \sup \frac{z(x)}{\psi\left(\xi_{1} G^{\beta}(d(x))\right)} \leq 1, \end{equation}
(4.6)

其中, \beta = \frac{k+1}{k} , \psi 是方程(2.1) 的解, 且

\xi_{1} = \frac{k}{k+1}\left(\frac{b_{1}}{M_{k-1}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)}\right)^{1 / k},

\xi_{2} = \frac{k}{k+1}\left(\frac{b_{2}}{m_{k-1}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)}\right)^{1 / k},

这里

\begin{eqnarray*} M_{k-1}: = \max _{\bar{x} \in \partial \Omega} S_{k-1}(\kappa_{1}(\bar{x}), \cdots , \kappa_{N-1}(\bar{x})) \mbox{ 和 } m_{k-1}: = \min _{\bar{x} \in \partial \Omega} S_{k-1}(\kappa_{1}(\bar{x}), \cdots , \kappa_{N-1}(\bar{x})). \end{eqnarray*}

   令

\begin{equation} \omega_{1}(d(x)) = G^{\beta}(d(x)), \quad \beta = \frac{k+1}{k}, \quad x \in \Omega_{\delta_{1}}. \end{equation}
(4.7)

\begin{equation} M_{k-1}: = \max\limits _{\bar{x} \in \partial \Omega} S_{k-1}(\kappa_{1}(\bar{x}), \cdots , \kappa_{N-1}(\bar{x}))   \mbox{ 和 }   m_{k-1}: = \min\limits _{\bar{x} \in \partial \Omega} S_{k-1}(\kappa_{1}(\bar{x}), \cdots , \kappa_{N-1}(\bar{x})). \end{equation}
(4.8)

固定 \epsilon \in (0, \min\{\frac{1}{2}, \frac{b_{1}}{2}\}) , 选取

\begin{equation} \begin{array}{ll} { }\xi_{1-} = \frac{k}{k+1}\left(\frac{(b_{1}-\epsilon)(1-\epsilon)-\epsilon}{M_{k-1}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)}\right)^{1 / k}, \\ { }\xi_{2+} = \frac{k}{k+1}\left(\frac{(b_{2}+\epsilon)(1+\epsilon)+\epsilon}{m_{k-1}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)}\right)^{1 / k}, \end{array} \end{equation}
(4.9)

其中, b_{1} b_{2} 在条件 (B_{3}) 中已经被给定. 利用引理2.1, 引理2.3, 有

G \in C^{2}(0, \delta_{0}) \bigcap C[0, \delta_{0})\quad(\delta_{0} > 0), \quad G(0) = 0

\omega_{1}(d(x)) = \int_{\psi(\omega_{1}(d(x)))}^{\infty} \frac{{\rm d}s}{(k f(s))^{\frac{1}{k}}},

可得

\lim\limits _{d(x) \rightarrow 0} \frac{G(d(x))}{g(d(x))} = 0,

\lim\limits _{d(x) \rightarrow 0} \frac{G(d(x))g^{\prime}(d(x))}{g^{2}(d(x))} = 1-G_{g},

\lim\limits _{d(x) \rightarrow 0} \frac{w_{1}(d(x)) f^{\prime}\left(\psi\left(w_{1}(d(x))\right)\right)}{\left(k f\left(\psi\left(w_{1}(d(x))\right)\right)\right)^{(k-1) / k}} = C^{+}_{f},

\lim\limits _{d(x) \rightarrow 0} \prod\limits_{j = 1}^{N-1} (1-d(x)\kappa_{j}(\bar{x})) = 1.

由(4.9) 式可得

m_{k-1}\beta^{k}\xi_{2+}^{k}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)-(b_{2}+\epsilon)(1+\epsilon) = \epsilon

M_{k-1}\beta^{k}\xi_{1-}^{k}\left(k G_{g}+\left(C^{+}_{f}-1\right)(k+1)\right)-(b_{1}-\epsilon)(1-\epsilon) = -\epsilon.

(Ⅰ) 当 g 非递减时, 基于条件 (B_{3}) , 可知存在与 \varepsilon 有关的充分小的 \delta_{\varepsilon} \in (0, \min\{1, \delta_{1}/2\}) 使得对于 \varrho \in (0, \delta_{\varepsilon})

\begin{equation} b(x) >\left(b_{1}-\varepsilon\right) g^{k+1}(d(x))\geq\left(b_{1}-\varepsilon\right) g^{k+1}(d(x)-\varrho), \quad x \in D_{\varrho}^{-} = \Omega_{2 \delta_{\varepsilon}} / \bar{\Omega}_{\varrho}, \end{equation}
(4.10)

\begin{equation} \left(b_{2}+\varepsilon\right) g^{k+1}(d(x)+\varrho)\geq\left(b_{2}+\varepsilon\right) g^{k+1}(d(x))>b(x), \quad x \in D_{\varrho}^{+} = \Omega_{2 \delta_{\varepsilon}-\varrho}, \end{equation}
(4.11)

\begin{equation} 1+\epsilon > \prod\limits_{j = 1}^{N-1} (1-d(x)\kappa_{j}(\bar{x}))>1-\epsilon, \quad x \in \Omega_{2 \delta_{\varepsilon}}, \end{equation}
(4.12)

且对于 x \in \Omega_{2 \delta_{\varepsilon}}

\begin{eqnarray*} &&k M_{k} \beta^{k} \xi_{1-}^{k} \frac{G(d(x))}{g(d(x))} \frac{\xi_{1-} w_{1}(d(x))f^{\prime}\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)\big)^{(k-1) / k}} \\ && +k M_{k-1} \beta^{k} \xi_{1-}^{k}\left(\beta \frac{\xi_{1-} w_{1}(d(x)) f^{\prime}\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)\big)^{(k-1) / k}}-\left(\beta-1+\frac{G(d(x)) g^{\prime}(d(x))}{g^{2}(d(x))}\right)\right) \\ && -\left(b_{1}-\varepsilon\right)(1-\varepsilon)<0 \end{eqnarray*}

\begin{eqnarray*} &&k m_{k} \beta^{k} \xi_{2+}^{k} \frac{G(d(x))}{g(d(x))} \frac{\xi_{2+} w_{1}(d(x)) f^{\prime}\big(\psi\left(\xi_{2+} w_{1}(d(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{2+}w_{1}(d(x))\right)\big)\big)^{(k-1) / k}}\\ &&+k m_{k-1} \beta^{k} \xi_{2+}^{k}\left(\beta \frac{\xi_{2+} w_{1}(d(x)) f^{\prime}\left(\psi\left(\xi_{2+} w_{1}(d(x))\right)\right)}{\big(k f\big(\psi\left(\xi_{2+} w_{1}(d(x))\right)\big)\big)^{(k-1) / k}}-\left(\beta-1+\frac{G(d(x)) g^{\prime}(d(x))}{g^{2}(d(x))}\right)\right)\\ &&-\left(b_{2}+\varepsilon\right)(1+\varepsilon)>0. \end{eqnarray*}

由(4.8) 式和(4.12) 式, 得

\begin{equation} \frac{m_{k-1}}{1+\epsilon} < S_{k-1}\left(\frac{\kappa_{1}(\bar{x})}{1-d(x) \kappa_{1}(\bar{x})}, \cdots , \frac{\kappa_{N-1}(\bar{x})}{1-d(x) \kappa_{N-1}(\bar{x})}\right)<\frac{M_{k-1}}{1-\epsilon}. \end{equation}
(4.13)

d_{1}(x) = d(x)-\varrho; \quad d_{2}(x) = d(x)+\varrho;

\begin{equation} \bar{z}_{\varepsilon} = \psi\left(\xi_{1-} w_{1}\left(d_{1}(x)\right)\right), x \in D_{\varrho}^{-} ; \quad \underline{z}_{\varepsilon} = \psi\left(\xi_{2+} w_{1}\left(d_{2}(x)\right)\right), x \in D_{\varrho}^{+}. \end{equation}
(4.14)

由(4.13) 式, 引理2.3和引理4.3, 可知对于 x \in D_{\varrho}^{-}

\begin{eqnarray*} &&S_{k}\left(\lambda\left(D^{2} \bar{z}_{\epsilon}\right)\right)-b(x) f\left(\bar{z}_{\epsilon}\right) \\ &\leq& S_{k}\left(\lambda\left(D^{2} \bar{z}_{\epsilon}\right)\right)-\left(b_{1}-\epsilon\right) g^{k+1}(d_{1}(x)) f\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big) \\ & = &\Big(-\xi_{1-} \beta g(d_{1}(x)) G^{\beta-1}(d_{1}(x)) \psi^{\prime}\left(\xi_{1-} w_{1}(d_{1}(x))\right)\Big)^{k} S_{k}\left(\frac{\kappa_{1}(\bar{x})}{1-d(x) \kappa_{1}(\bar{x})}, \cdots , \frac{\kappa_{N-1}(\bar{x})}{1-(x) \kappa_{N-1}(\bar{x})}\right) \\ &&+\Big(-\xi_{1-} \beta g(d_{1}(x)) G^{\beta-1}(d_{1}(x)) \psi^{\prime}\left(\xi_{1-} w_{1}(d_{1}(x))\right)\Big)^{k-1} \xi_{1-} \beta G^{\beta-2}(d_{1}(x))g^{2}(d_{1}(x)) \\ &&\times \left(\xi_{1-} \beta G^{\beta}(d_{1}(x)) \psi^{\prime \prime}\left(\xi_{1-} w_{1}(d_{1}(x))\right)+\psi^{\prime}\left(\xi_{1-} w_{1}(d_{1}(x))\right)\left(\beta-1+\frac{G(d_{1}(x)) g^{\prime}(d_{1}(x))}{g^{2}(d_{1}(x))}\right)\right)\\ && \times S_{k-1}\left(\frac{\kappa_{1}(\bar{x})}{1-d(x) \kappa_{1}(\bar{x})}, \cdots , \frac{\kappa_{N-1}(\bar{x})}{1-d(x) \kappa_{N-1}(\bar{x})}\right)-\left(b_{1}-\varepsilon\right) g^{k+1}\left(d_{1}(x)\right) f\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big) \\ &\leq&\frac{g^{k+1}(d_{1}(x))}{1-\epsilon} f\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big)\left(k M_{k} \beta^{k} \xi_{1-}^{k} \frac{G(d_{1}(x))}{g(d_{1}(x))} \frac{\xi_{1-} w_{1}(d_{1}(x)) f^{\prime}\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big)\big)^{(k-1) / k}} \right. \\ &&\left.\quad+k M_{k-1} \beta^{k} \xi_{1-}^{k}\left(\beta \frac{\xi_{1-} w_{1}(d_{1}(x)) f^{\prime}\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{1-} w_{1}(d_{1}(x))\right)\big)\big)^{(k-1) / k}}-\left(\beta-1+\frac{G(d_{1}(x))g^{\prime}(d_{1}(x))}{g^{2}(d_{1}(x))}\right)\right) \right.\\ && \Bigg.-\left(b_{1}-\varepsilon\right)(1-\varepsilon)\Bigg) \leq 0, \end{eqnarray*}

这表明在 D_{\varrho}^{-} 中, \bar{z}_{\varepsilon} k -Hessian问题(1.1) 的上解.

显然, 在 D_{\varrho}^{-} 中, D^{2} \bar{z}_{\varepsilon}>0 . 结合引理4.2和4.3的证明, 利用(4.2) 式和引理2.3中 (1) (3) , 可得矩阵 D^{2} \bar{z}_{\varepsilon} l 阶主子式

\begin{eqnarray*} &&\left(-\xi_{1-} \beta G^{\beta-1}\left(d_{1}(x)\right) g\left(d_{1}(x)\right) \psi^{\prime}\left(\xi_{1-} w_{1}\left(d_{1}(x)\right)\right)\right)^{l} \prod\limits_{j = 1}^{l} \frac{\kappa_{j}(\bar{x})}{1-d(x) \kappa_{j}(\bar{x})} \\ & = &\left(\beta \xi_{1-}\right)^{l} G^{l / k}\left(d_{1}(x)\right) g^{l}\left(d_{1}(x)\right)\left(k f\left(\psi\left(\xi_{1-} w_{1}\left(d_{1}(x)\right)\right)\right)\right)^{l / k} \prod\limits_{j = 1}^{l} \frac{\kappa_{j}(\bar{x})}{1-d(x) \kappa_{j}(\bar{x})} > 0, \end{eqnarray*}

其中, l = 1, 2, \cdots , N-1 . 因此, 在 D_{\varrho}^{-} 中, 矩阵 D^{2} \bar{z}_{\varepsilon} 是正定的.

类似地, 可证在 D_{\varrho}^{+} 中, \underline{z}_{\varepsilon} = \psi\left(\xi_{2+} w_{1}\left(d_{2}(x)\right)\right) k -Hessian问题(1.1) 的下解且矩阵 D^{2} \underline{z}_{\varepsilon} 是正定的.

z \in C^{2}(\Omega) k -Hessian问题(1.1) 的一个严格凸解且 C_{0} > 0 充分大可使得

\begin{equation} z\leq \bar{z}_{\varepsilon}+C_{0}, \quad d(x) = 2\delta_{\varepsilon}; \quad \underline{z}_{\varepsilon}\leq z+C_{0}, \quad d(x) = 2\delta_{\varepsilon}-\varrho. \end{equation}
(4.15)

显然, \lim\limits _{d_{1}(x) \rightarrow \varrho}\bar{z}_{\varepsilon}(x) = \infty , z\mid_{\partial \Omega} = +\infty > \underline{z}_{\epsilon}\mid_{\partial \Omega} . 由引理4.1可得

\begin{equation} z\leq \bar{z}_{\varepsilon}+C_{0}, \quad x \in D_{\varrho}^{-}, \quad \underline{z}_{\varepsilon}\leq z+C_{0}, \quad x \in D_{\varrho}^{+}, \end{equation}
(4.16)

1-\frac{C_{0}}{\psi\left(\xi_{2+} w_{1}\left(d_{2}(x)\right)\right)} \leq \frac{z(x)}{\psi\left(\xi_{2+} w_{1}\left(d_{2}(x)\right)\right)}, \quad x \in D_{\varrho}^{+}

\frac{z(x)}{\psi\left(\xi_{1-} w_{1}\left(d_{1}(x)\right)\right)} \leq 1+\frac{C_{0}}{\psi\left(\xi_{1-} w_{1}\left(d_{1}(x)\right)\right)}, \quad x \in D_{\varrho}^{-}.

对于 x \in D_{\varrho}^{-} \cap D_{\varrho}^{+} , 令 \varrho \rightarrow 0 , 有

1-\frac{C_{0}}{\psi\left(\xi_{2+} w_{1}\left(d(x)\right)\right)} \leq \frac{z(x)}{\psi\left(\xi_{2+} w_{1}\left(d(x)\right)\right)}

\frac{z(x)}{\psi\left(\xi_{1-} w_{1}\left(d(x)\right)\right)} \leq 1+\frac{C_{0}}{\psi\left(\xi_{1-} w_{1}\left(d(x)\right)\right)},

\begin{equation} 1 \leq \lim\limits _{d(x) \rightarrow 0} \inf \frac{z(x)}{\psi\left(\xi_{2+} w_{1}\left(d(x)\right)\right)} \quad \mbox{ 和 } \quad \lim\limits _{d(x) \rightarrow 0} \sup \frac{z(x)}{\psi\left(\xi_{1-} w_{1}\left(d(x)\right)\right)} \leq 1, \end{equation}
(4.17)

进一步, 在(4.17) 式中, 令 \varepsilon \rightarrow 0 可得(4.6) 式.

(Ⅱ) 当 g 非递增时, 令

\omega_{2}(d(x)): = (G(d(x))-G(\varrho))^{\beta}, \quad d(x)>\varrho>0.

由引理2.3和条件 (B_{3})

\begin{equation} \lim\limits _{(d(x), \varrho) \rightarrow (0, 0)} \frac{w_{2}(d(x)) f^{\prime}\left(\psi\left(w_{2}(d(x))\right)\right)}{\left(k f\left(\psi\left(w_{2}(d(x))\right)\right)\right)^{(k-1) / k}} = C^{+}_{f}, \end{equation}
(4.18)

且存在与 \epsilon 有关的充分小的 \delta_{\epsilon} \in (0, \min\{1, \delta_{1}/2\}) 使得

\begin{equation} \left(b_{1}-\varepsilon\right) g^{k+1}(d(x)) \leq b(x)\leq \left(b_{2}+\varepsilon\right) g^{k+1}(d(x)), x \in \Omega_{2 \delta_{\varepsilon}}. \end{equation}
(4.19)

\varrho \in (0, \delta_{\epsilon}) ,

\begin{equation} \bar{z}_{\varepsilon} = \psi\left(\xi_{1-} w_{2}\left(d(x)\right)\right), x \in D_{\varrho}^{-}, \end{equation}
(4.20)

利用引理2.1, 引理4.3, (4.18) 式, (4.19) 式, 可得

0< \frac{G(d(x))-G(\varrho)}{G(d(x))} <1

\lim\limits _{d(x) \rightarrow 0} \frac{G(d(x))g^{\prime}(d(x))}{g^{2}(d(x))} = 1-G_{g}\leq 0,

对于 x \in D_{\varrho}^{-} , 有

\begin{eqnarray*} &&S_{k}\left(\lambda\left(D^{2} \bar{z}_{\epsilon}\right)\right)-b(x) f\left(\bar{z}_{\epsilon}\right) \\ &\leq& S_{k}\left(\lambda\left(D^{2} \bar{z}_{\epsilon}\right)\right)-\left(b_{1}-\epsilon\right) g^{k+1}(d(x)) f\left(\psi\left(\xi_{1-} w_{2}(d(x))\right)\right) \\ & = &\Big(-\xi_{1-} \beta g(d(x)) G^{\beta-1}(d(x)) \psi^{\prime}\left(\xi_{1-} w_{2}(d(x))\right)\Big)^{k} S_{k}\left(\frac{\kappa_{1}(\bar{x})}{1-d(x) \kappa_{1}(\bar{x})}, \cdots , \frac{\kappa_{N-1}(\bar{x})}{1-d(x) \kappa_{N-1}(\bar{x})}\right) \\ &&+\Big(-\xi_{1-} \beta g(d(x)) G^{\beta-1}(d(x)) \psi^{\prime}\left(\xi_{1-} w_{2}(d(x))\right)\Big)^{k-1} \xi_{1-} \beta G^{\beta-2}(d(x))g^{2}(d(x)) \\ && \times \left(\xi_{1-} \beta G^{\beta}(d(x)) \psi^{\prime \prime}\left(\xi_{1-} w_{2}(d(x))\right)+\psi^{\prime}\left(\xi_{1-} w_{2}(d(x))\right)\left(\beta-1+\frac{G(d(x)) g^{\prime}(d(x))}{g^{2}(d(x))}\right)\right)\\ && \times S_{k-1}\left(\frac{\kappa_{1}(\bar{x})}{1-d(x) \kappa_{1}(\bar{x})}, \cdots , \frac{\kappa_{N-1}(\bar{x})}{1-d(x) \kappa_{N-1}(\bar{x})}\right)-\left(b_{1}-\varepsilon\right) g^{k+1}\left(d_{1}(x)\right) f\big(\psi\left(\xi_{1-} w_{2}(d(x))\right)\big) \\ &\leq&\frac{g^{k+1}(d(x))}{1-\epsilon} f\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)\left(k M_{k} \beta^{k} \xi_{1-}^{k} \frac{G(d(x))}{g(d(x))} \frac{\xi_{1-} w_{1}(d(x)) f^{\prime}\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)}{\big(k f\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)\big)^{(k-1) / k}} \right. \\ &&+k M_{k-1} \beta^{k} \xi_{1-}^{k}\bigg(\beta \frac{\xi_{1-} w_{1}(d(x)) f^{\prime} \big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)} {\big(k f\big(\psi\left(\xi_{1-} w_{1}(d(x))\right)\big)\big)^{(k-1)/ k}} \\ && -\bigg(\beta-1+\frac{G(d(x))g^{\prime}(d(x))}{g^{2}(d(x))} \frac{G(d(x))-G(\varrho)}{G(d(x))}\bigg)\bigg) -\left(b_{1}-\varepsilon\right)(1-\varepsilon)\Bigg) \leq 0, \end{eqnarray*}

这表明在 D_{\varrho}^{-} 中, \overline{z}_{\epsilon} k -Hessian问题(1.1) 的上解. 类似地, 可证

\begin{equation} \underline{z}_{\varepsilon} = \psi\left(\xi_{2+} \left(G(d(x))+G(\varrho)\right)^{\beta} \right), x \in D_{\varrho}^{+}, \end{equation}
(4.21)

D_{\varrho}^{+} 中, \underline{z}_{\epsilon} k -Hessian问题(1.1) 的下解.

显然, 根据(Ⅰ) 中相同的证明可知(4.6) 式在(Ⅱ) 中依然成立. 证毕.

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