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数学物理学报, 2019, 39(2): 277-285 doi:

论文

一类具有偏差变元的p-Laplacian Liénard型方程在吸引奇性条件下周期解的存在性

程志波1,2, 毕中华1, 姚绍文,1

Periodic Solution for p-Laplacian Liénard Equation with Attractive Singularity and Time-Dependent Deviating Argument

Cheng Zhibo1,2, Bi Zhonghua1, Yao Shaowen,1

通讯作者: 姚绍文, E-mail: yaoshaowen@hpu.edu.com

收稿日期: 2017-11-9  

基金资助: 国家自然科学基金.  11501170
国家自然科学基金.  71601072
中国博士后基金.  2016M590886
河南省高校基本科研业务费专项资金.  NSFRF170302
河南理工大学博士基金.  B2013-055

Received: 2017-11-9  

Fund supported: the NSFC.  11501170
the NSFC.  71601072
the China Postdoctoral Science Foundation.  2016M590886
the Fundamental Research Funds for the Universities of Henan Provience.  NSFRF170302
the Henan Polytechnic University Doctor Fund.  B2013-055

摘要

该文考虑了一类具有偏差变元的奇性p-Laplacian Liénard型方程

(φp(x(t)))+f(x(t))x(t)+g(t,x(tσ(t)))=e(t),

其中g(x)在原点处具有吸引奇性.通过应用Manásevich-Mawhin连续定理和一些分析方法,证明了这个方程周期解的存在性.

关键词: Liénard型方程 ; 周期解 ; 吸引奇性 ; p-Laplacian ; 偏差变元

Abstract

In this paper, we consider a kind of p-Laplacian singular Liénard equation with time-dependent deviating argument

(φp(x(t)))+f(x(t))x(t)+g(t,x(tσ(t)))=e(t),

where g has a attractive singularity at x=0. By applications of Manásevich-Mawhin continuation theorem and some analysis skills, sufficient conditions for the existence of periodic solution is established.

Keywords: Liénard equation ; Periodic solution ; Attractive singularity ; p-Laplacian ; Time-dependent deviating argument

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本文引用格式

程志波, 毕中华, 姚绍文. 一类具有偏差变元的p-Laplacian Liénard型方程在吸引奇性条件下周期解的存在性. 数学物理学报[J], 2019, 39(2): 277-285 doi:

Cheng Zhibo, Bi Zhonghua, Yao Shaowen. Periodic Solution for p-Laplacian Liénard Equation with Attractive Singularity and Time-Dependent Deviating Argument. Acta Mathematica Scientia[J], 2019, 39(2): 277-285 doi:

1 引言

近些年来,在对Liénard型方程的周期解的研究中,越来越多的学者把注意力放在了奇性Liénard型方程(参见文献[1-14]).事实上,这是由于奇性方程在应用科学和物理中有重大的意义背景,比如Brillouin电子束聚焦问题(参见文献[3, 13]).在这些研究中,关于Liénard型方程在排斥奇性下的研究可追溯到1996年.章梅荣(参见文献[14])讨论了在奇性条件下Liénard型方程的正周期解的存在性

x
(1.1)

其中f:\mathbb{R} \to\mathbb{R} 是连续的, g:\mathbb{R} \times(0, \infty)\to\mathbb{R} 是一个L^{2}-Carathéodory函数,且当x\to0^+时, g(t, x(t))是无界的.若g(t, x(t))\to-\infty,则方程(1.1)是在排斥奇性下的Liénard型方程;或者g(t, x(t))\to+\infty,方程(1.1)是在吸引奇性下的Liénard型方程.为证明方程(1.1)至少存在一个T周期解,章梅荣给出了下列条件.

(H_1)存在两个正常数0 < D_1 < D_2使得当x是正T周期连续函数时满足

\int^T_0 g(t, x(t)){\rm d}t=0,

则有

D_1\leq x(\tau)\leq D_2,

其中\tau\in[0, T].

(H_2)存在0 < D_1 < D_2,对所有的x\in(0, D_1)\overline{g}(x):=\frac{1}{T}\int^T_0g(t, x(t)){\rm d}t < 0,和对所有的x>D_2\overline{g}(x)>0.

(H_3)g(t, x(t))=g_0(x)+g_1(t, x(t)),其中g_0\in C((0, \infty), \mathbb{R})g_1:[0, T]\times[0, \infty)\to\mathbb{R} 是一个L^{2}-Carathéodory函数.

(H_4)假设对于处处连续的t\in[0, T],存在

\psi(t)=\limsup\limits_{x\rightarrow+\infty}\frac{g(t, x(t))}{x},

即:对于任意的\varepsilon>0,有g_\varepsilon\in L^2(0, T)使得

g(t, x(t))\leq(\psi(t)+\varepsilon)x+g_\varepsilon(t),

其中x>0t\in[0, T]上处处连续.同时有\psi\in C(\mathbb{R}, \mathbb{R})\psi(t+T)=\psi(t).

(H_5) (在x=0处的排斥奇性条件) \int^1_0g_0(x){\rm d}x=-\infty.

定理1.1  假设条件(H_1)-(H_5)成立.若有\|\psi^+\|_1 < \frac{\sqrt{3}}{T},其中\|\psi^+\|_1:=\int^T_0|\psi^+(t)|{\rm d}t\psi^+(t):=\max(\psi(t), 0)成立,则方程(1.1)至少有一个正T周期解.

王在洪[11]在2014年研究了具有常时滞奇性Liénard型方程的周期解的存在性

\begin{equation}{\label{eq1.2}}x''(t)+f(x(t))x'(t)+g(t, x(t-\sigma))=0, \end{equation}
(1.2)

其中\sigma是常数且0\leq\sigma < T.通过应用Mawhin's连续性定理,作者证明了下面的定理.

定理1.2  假设条件(H_1)-(H_5)成立.则方程(1.2)至少有一个T周期解若有\|\psi\| < \left(\frac{\pi}{T}\right)^2成立,其中\|\psi\|:=\max\limits_{t\in\mathbb{R} }|\psi(t)|.

最近,辛云和程志波[12]在2016年研究了下面的一类具有常时滞奇性的p-Laplacian Liénard型方程

\begin{equation}{\label{eq1.3a}}(\varphi_p(x'(t)))'+f(x(t))x'(t)+g(t, x(t-\sigma))=e(t), \end{equation}
(1.3)

其中\varphi_p(s)=|s|^{p-2}s\varphi_p:\mathbb{R} \to\mathbb{R} ,这里的p是一个常数; e:\mathbb{R} \to\mathbb{R} 是一个连续的周期函数有e(t+T)=e(t)\int^T_0e(t){\rm d}t=0.作者证明了方程(1.3)至少存在一个T周期解.

定理1.3  假设条件(H_1)-(H_3)和(H_5)成立.同时,有下列条件成立

(H'_4)假设

\psi(t)=\limsup\limits_{x\rightarrow+\infty}\frac{g(t, x)}{x^{p-1}}

存在且t\in[0, T]处处连续,即,对任意的\varepsilon>0存在g_\varepsilon\in L^2(0, T)使得

g(t, x)\leq(\psi(t)+\varepsilon)x^{p-1}+g_\varepsilon(t)

成立,其中x>0t\in[0, T]处处连续.同时

\psi\inC(\mathbb{R} , \mathbb{R} )~\mbox{且}~ \psi(t+T)=\psi(t).

则方程(1.3)至少存在一个T周期解,若有

\left(\frac{T}{\pi_p}\right)^p\|\psi\| <1

成立,其中\pi_p=2\int^{(p-1)/p}_0\frac{ds}{(1-\frac{s^p}{p-1})^{1/p}}=\frac{2\pi(p-1)^{1/p}}{p\sin(\pi/p)}.

以上所提及的结论都是Liénard型方程在排斥奇性条件下或者是具有时滞的Liénard型方程相关的.自然而然地有新的问题产生:关于具有偏差变元的Liénard型方程在吸引奇性条件下的周期解的存在性呢?除了实际意义,该问题有显著的理论意义.为了回答这个问题,在本文中,我们讨论了下面具有偏差变元的奇性Liénard型方程

\begin{equation}{\label{eq1.3}}(\varphi_p(x'(t)))'+f(x(t))x'(t)+g(t, x(t-\sigma(t)))=e(t), \end{equation}
(1.4)

其中\sigma(t)\in C^1(\mathbb R, \mathbb R)是一个T周期函数且有\sigma'(t) < 1.显然,吸引奇性条件\lim\limits_{x\rightarrow0^+}\int^1_{x}g_0(x)=+\infty与条件(H_2)和(H_4) (或者(H_4'))是矛盾的.因此,在文献[11-12, 14]中的方法已经不再适用于证明方程(1.4)在吸引奇性条件下的周期解的存在性.因此我们将寻找新的方法来解决.

在本文中,通过应用Manásevich-Mawhin连续性定理,我们证明了下面的定理.

定理1.4  若条件(H_3)成立.设有下列条件成立

(H_2')存在0 < D_1 < D_2,对所有的x\in(0, D_1)\overline{g}(x)>0和对所有的x>D_2\overline{g}(x) < 0.

(H_5') (在x=0处的吸引奇性条件)

\int^1_0g_0(x){\rm d}x=+\infty.

(H_6)存在两个正常数ab使得

-g(t, x)\leq ax^{p-1}+b, ~~t\in[0, T] ~~\mbox{且}~~ x>0.

如果\frac{aT^{p}}{2^{p-1}} < 1,则方程(1.4)至少存在一个T周期解.

注1.1  当\sigma(t)\equiv \sigma时(其中\sigma是任意一个常数),方程(1.4)可变化为方程(1.3).此外,当p=2\sigma(t)=\sigma时,方程(1.4)可化为方程(1.1)和方程(1.2).因此,定理1.4可看作是定理1.1,定理1.2和定理1.3的综合结论.

2 定理1.4的证明

对于T -周期的边值问题

\begin{equation}{\label{eq2.1}} (\varphi_p(x'(t)))'=\tilde{f}(t, x, x'), \end{equation}
(2.1)

其中\tilde{f}:[0, T]\times\mathbb{R} \times\mathbb{R} \rightarrow\mathbb{R} 被认为是Carathéodory函数.

引理2.1 (Manásevich-Mawhin[7])令\Omega是在C^1_T:=\{x\in C^1(\mathbb{R}, \mathbb{R}): x \mbox{是}T-周期的\}上的有界开集.满足下列条件

(ⅰ)对每一个\lambda\in(0, 1),

(\varphi_p(x'(t)))'=\lambda\tilde{f}(t, x, x'), x(0)=x(T), x'(0)=x'(T)

\partial\Omega上没有解;

(ⅱ)方程

F(a):=\frac{1}{T}\int^T_0\tilde{f}(a, x(a), 0){\rm d}t=0

\partial\Omega\cap\mathbb{R} 上没有解;

(ⅲ) F的Brouwer度

\deg\{F, \partial\Omega\cap\mathbb{R} , 0\}\neq0.

则周期边值方程(2.1)在\bar{\Omega}上至少有一个周期解.

定理1.4的证明  考虑方程(1.4)的同伦方程

\begin{equation}{\label{eq3.1}}(\varphi_p(x'(t)))'+\lambda f(x(t))x'(t)+\lambda g(t, x(t-\sigma(t)))=\lambda e(t).\end{equation}
(2.2)

首先,我们断言方程(2.2)的所有可能的解都是有界的.令x(t)\in C^1_T是方程(2.2)的任意一个T周期解.

对方程(2.2)左右两边进行在[0, T]上的积分,我们得到

\int^T_0(\varphi_p(x'(t)))'{\rm d}t+\lambda\int^T_0f(x(t))x'(t){\rm d}t+\lambda\int^T_0g(t, x(t-\sigma(t))){\rm d}t=\lambda\int^T_0e(t){\rm d}t.

由于\int^T_0(\varphi_p(x'(t)))'{\rm d}t=0, \int^T_0f(x(t))x'(t){\rm d}t=0\int^T_0e(t){\rm d}t=0,可得

\begin{equation}{\label{eq3.2}}\int^T_0g(t, x(t-\sigma(t))){\rm d}t=0.\end{equation}
(2.3)

由条件(H'_2)g(x)的连续性可知,存在一点\xi\in(0, T)使得

D_1\leq x(\xi-\sigma(\xi))\leq D_2.

\tau=\xi-\sigma(\xi)\in[0, T],则有

\begin{equation}{\label{eq2.5}}D_1\leq x(\tau)\leq D_2.\end{equation}
(2.4)

因此,我们有

\begin{eqnarray}{\label{eq3.3}}\|x\|&=&\max\limits_{t\in[0, T]}|x(t)|=\max\limits_{t\in[\tau, \tau+T]}|x(t)|\\ &=&\frac{1}{2}\max\limits_{t\in[\tau, \tau+T]}\left(|x(t)|+|x(t-T)|\right)\\ &=&\frac{1}{2}\max\limits_{t\in[\tau, \tau+T]}\left(\left|x(\tau)+\int^t_{\tau}x'(s){\rm d}s\right| +\left|x(\tau)-\int^{\tau}_{t-T}x'(s){\rm d}s\right|\right)\\& \leq &D_2+\frac{1}{2}\left(\int^t_\tau|x'(s)|{\rm d}s+\int^\tau_{t-T}|x'(s)|{\rm d}s\right)\\ &\leq& D_2+\frac{1}{2}\int^T_0|x'(s)|{\rm d}s. \end{eqnarray}
(2.5)

方程(2.2)等式两边同时乘以x(t)且在[0, T]上积分,可得

\begin{eqnarray}{\label{eq3.6}}&&\int^T_0(\varphi_p(x'(t)))'x(t){\rm d}t+\lambda\int^T_0f(x(t))x'(t)x(t){\rm d}t+\lambda\int^T_0g(t, x(t-\sigma(t)))x(t){\rm d}t\\&=&\lambda\int^T_0e(t)x(t){\rm d}t.\end{eqnarray}
(2.6)

\int^T_0(\varphi_p(x'(t)))'x(t){\rm d}t=-\int^T_0|x'(t)|^{p}{\rm d}t\int^T_0f(x(t))x'(t)x(t){\rm d}t=0代入方程(2.6),有

-\int^T_0|x'(t)|^{p}{\rm d}t=-\lambda\int^T_0g(t, x(t-\sigma(t)))x(t){\rm d}t+\lambda\int^T_0e(t)x(t){\rm d}t.

故而有

\begin{eqnarray}{\label{eq3.6a}}\int^T_0|x'(t)|^{p}{\rm d}t&\leq&\int^T_0|g(t, x(t-\sigma(t)))||x(t)|{\rm d}t+\int^T_0|e(t)||x(t)|{\rm d}t\\ &\leq&\|x\|\int^T_0|g(t, x(t-\sigma(t)))|{\rm d}t+\|x\|\int^T_0|e(t)|{\rm d}t.\end{eqnarray}
(2.7)

由条件(H_6)和方程(2.3)可得

\begin{eqnarray}{\label{eq3.7}}\int^T_0|g(t, x(t-\sigma(t)))|{\rm d}t&=&\int_{g(t, x(t-\sigma(t)))>0}g^{+}(t, x(t-\sigma(t))){\rm d}t\\&&- \int_{g(t, x(t-\sigma(t)))\leq0}g^{-}(t, x(t-\sigma(t))){\rm d}t\\ &=&-2\int_{g(t, x(t-\sigma(t)))\leq0}g^{-}(t, x(t-\sigma(t))){\rm d}t\\ &\leq& 2\int^T_0(ax^{p-1}+b){\rm d}t\\ &\leq&2aT\|x\|^{p-1}+2bT, \end{eqnarray}
(2.8)

其中g^{-}:=\min\{g(t, x(t-\sigma(t))), 0\}.将方程(2.8)代入方程(2.7)得

\begin{equation}{\label{eq3.8}}\int^T_0|x'(t)|^{p}{\rm d}t\leq2aT\|x\|^{p}+\|x\|(2bT+\|e\|T).\end{equation}
(2.9)

将方程(2.5)代入方程(2.9)可得

\begin{eqnarray}{\label{eq3.9}}\int^T_0|x'(t)|^{p}{\rm d}t&\leq&2aT\left(D_2+\frac{1}{2}\int^T_0|x'(t)|{\rm d}t\right)^{p}+(2bT+\|e\|T)\left(D_2+\frac{1}{2}\int^T_0|x'(t)|{\rm d}t\right)\\&\leq&2aT\left(\left(\frac{1}{2}\int^T_0|x'(t)|{\rm d}t\right)^{p}+pD_2\left(\frac{1}{2}\int^T_0|x'(t)|{\rm d}t\right)^{p-1}+\cdots+D^{p}_2\right)\\&&+(2bT+\|e\|T)\frac{\int^T_0|x'(t)|{\rm d}t}{2}+(2bT+\|e\|T)D_2\\&=&\frac{aT}{2^{p-1}}\left(\int^T_0|x'(t)|{\rm d}t\right)^{p}+\frac{pD_2}{2^{p-1}}\left(\int^T_0|x'(t)|{\rm d}t\right)^{p-1}+\cdots+2aTD^p_2\\&&+\frac{2bT+\|e\|T}{2}\int^T_0|x'(t)|{\rm d}t+(2bT+\|e\|T)D_2.\end{eqnarray}
(2.10)

由Hölder不等式,我们可以得到

\begin{eqnarray}{\label{3.11}}\int^T_0|x'(t)|^{p}{\rm d}t&\leq&\frac{aT}{2^{p-1}}\left(T^{\frac{1}{q}}\left(\int^T_0|x'(t)|^{p}{\rm d}t\right)^{\frac{1}{p}}\right)^{p}+\frac{pD_2}{2^{p-1}}\left(T^{\frac{1}{q}}\left(\int^T_0|x'(t)|^{p}{\rm d}t\right)^{\frac{1}{p}}\right)^{p-1}\\&&+\cdots+2aTD^p_2+\frac{2bT+\|e\|T}{2}T^{\frac{1}{q}}\left(\int^T_0|x'(t)|^{p}{\rm d}t\right)^{\frac{1}{p}}+(2bT+\|e\|T)D_2\\&=&\frac{aT^{p}}{2^{p-1}}\int^T_0|x'(t)|^{p}{\rm d}t+\frac{pD_2}{2^{p-1}}\left(T^{\frac{1}{q}}\left(\int^T_0|x'(t)|^{p}{\rm d}t\right)^{\frac{1}{p}}\right)^{p-1}+\cdots+2aTD^p_2\\&&+\frac{2bT+\|e\|T}{2}T^{\frac{1}{q}}\left(\int^T_0|x'(t)|^{p}{\rm d}t\right)^{\frac{1}{p}}+(2bT+\|e\|T)D_2.\end{eqnarray}
(2.11)

\frac{aT^{p}}{2^{p-1}} < 1,很容易得到存在一个常数M_1'>0 (不依赖于\lambda),使得

\begin{equation}{\label{eq3.12}}\int^T_0|x'(t)|^p{\rm d}t\leq M_1'.\end{equation}
(2.12)

由方程(2.5)和方程(2.12),我们有

\begin{equation}{\label{eq3.13}}\|x\|\leq D_2+\frac{1}{2}\int^T_0|x'(s)|{\rm d}s\leq D_2+\frac{T^{\frac{1}{q}}}{2}(M_1')^{\frac{1}{p}}:=M_1.\end{equation}
(2.13)

因为x(t)T周期的,则存在一点t_0\in(0, T)使得x'(t_0)=0,然而\varphi_p(0)=0.因此,由方程(2.8)和方程(2.13),我们得

\begin{eqnarray}{\label{eq3.14}}|\varphi_p(x'(t))|&=&\left|\int^t_{t_0}(\varphi_p(x'(s)))'{\rm d}s\right|\\&\leq&\lambda\int^T_0|f(x(t))||x'(t)|{\rm d}t+\lambda\int^T_0|g(t, x(t-\sigma(t)))|{\rm d}t+\lambda\int^T_0|e(t)|{\rm d}t\\&\leq&\|f_{M_1}\|T^{\frac{1}{q}}(M'_1)^{\frac{1}{p}}+2aTM_1^{p-1}+2bT+T\|e\|:=M'_2, \end{eqnarray}
(2.14)

其中\|f_{M_1}\|:=\max\limits_{|x(t)|\leq M_1}|f(x(t))|.接下来我们断言存在一个正常数M_2>M_2'+1,使得对于所有的t\in\mathbb{R} ,我们有

\begin{equation}{\label{eq3.15}}\|x'\|\leq M_2.\end{equation}
(2.15)

事实上,如果x'(t)是无界的;则存在一个正常数M''_2使得\|x'\|>M''_2对于某些x'(t)\in\mathbb{R} 成立,因此,我们得到\|\varphi_p(x')\|=\|x'\|^{p-1}\geq(M''_2)^{p-1}.则它是矛盾的,于是方程(2.15)成立.

另一方面,由方程(2.2)和g(t, x(t))=g_0(x(t))+g_1(t, x(t))

\begin{equation}{\label{eq3.16}}(\varphi_p(x'(t)))'+\lambda f(x(t))x'(t)+\lambda(g_0(t-\sigma(t))+g_1(t, x(t-\sigma(t))))=\lambda e(t).\end{equation}
(2.16)

\tau\in[0, T]且满足方程(2.4)的定义,方程(2.16)两边同时乘以x'(t-\sigma(t))(1-\sigma'(t))且在[\tau, t]上积分,得

\begin{eqnarray*}\lambda\int^{x(t-\sigma(t))}_{x(\tau-\sigma(\tau))}g_0(u){\rm d}u&=&\lambda\int^t_{\tau}g_0(x(s-\sigma(s)))x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\\&=&-\int^t_{\tau}(\varphi_p(x'(s)))'x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\\&& -\lambda\int^t_{\tau}f(x(s))x'(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\\&&-\lambda\int^t_{\tau}g_1(s, x(s-\sigma(s)))x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\\&&+\lambda\int^t_{\tau}e(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s.\end{eqnarray*}

进一步,有

\begin{eqnarray}{\label{eq3.18}}\lambda\left|\int^{x(t-\sigma(t))}_{x(\tau-\sigma(\tau))}g_0(v){\rm d}v\right|&\leq&\left|\int^t_{\tau}(\varphi_p(x'(s)))'x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right| \\&& +\lambda\left|\int^t_{\tau}f(x(s))x'(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|\\&&+\lambda\left|\int^t_{\tau}g_1(s, x(s-\sigma(s)))x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|\\&& +\lambda\left|\int^t_{\tau}e(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|.\end{eqnarray}
(2.17)

由方程(2.14)和方程(2.15),我们可得

\begin{eqnarray*}&& \left|\int^t_{\tau}(\varphi_p(x'(s)))'x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right| \\ &\leq&\int^t_{\tau}|(\varphi_p(x'(s)))'||x'(s-\sigma(s))||1-\sigma'(s)|{\rm d}s\\ &\leq&\sigma^1\|x'\|\int^T_0|(\varphi_p(x'(s)))'|{\rm d}s\\ & \leq&\lambda\sigma^1M_2\left(\int^T_0|f(x(s))||x'(s)|{\rm d}s+\int^T_0|g(s, x(s-\sigma(s)))|{\rm d}s+\int^T_0|e(s)|{\rm d}s\right)\\ & \leq&\lambda\sigma^1 M_2(|f|_{M_1} M_2T+2aT(M_1)^{p-1}+2bT+T\|e\|), \end{eqnarray*}

其中|f|_{M_1}:=\max\limits_{0 < x\leq M_1}|f(x)|, \sigma^1:=\max\limits_{t\in[0, T]}|1-\sigma'(t)|.同时,我们有

\left|\int^t_{\tau}f(x(s))x'(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|\leq\sigma^1M_2^2\int^T_0|f(x(s))|{\rm d}s\leq \sigma^1M_2^2 T|f|_{M_1},

\left|\int^t_{\tau}g_1(s, x(s-\sigma(s)))x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|\leq\sigma^1M_2\sqrt{T}\|g_{M_1}\|_2,

\left|\int^t_{\tau}e(s)x'(s-\sigma(s))(1-\sigma'(s)){\rm d}s\right|\leq\sigma^1M_2T\|e\|,

这里\|g_{M_1}\|=\max\limits_{0 < x\leq M_1}|g_1(t, x)|\in L^2(0, T).

由以上不等式,我们可得方程(2.17)为

\left|\int^{x(t-\sigma(t))}_{x(\tau-\sigma(\tau))}g_0(u){\rm d}u\right|\leq\sigma^1\left(2M_2T\left(M_2|f|_{M_1}+a(M_1)^{p-1}+b+\frac{1}{2\sqrt{T}}\|g_{M_1}\|_2+\|e\|\right)\right).

由强吸引奇性条件(H_5'),存在一个正常数M_3>0使得

\begin{equation}{\label{eq3.20}} x(t-\sigma(t))\geq M_3,~~ \forall t\in[\tau, T].\end{equation}
(2.18)

v=t-\sigma(t),则我们有

x(v)\geq M_3,~~ \forall v\in[\tau-\sigma(\tau), T-\sigma(T)].

同理可得t\in[0, \tau] (即v\in[-\sigma(0), \tau-\sigma(\tau)]).

定义

\Omega=\{x\in C^1_T(\mathbb{R} , \mathbb{R} )| E_1\leq x(t)\leq E_2, \|x'\|\leq M_2, \forall t\in[0, T]\},

这里E_1 < \min\{D_1, M_3\}, E_2>\max\{D_2, M_1\}.且可知对于\lambda\in(0, 1),方程(2.2)在\partial\Omega上没有解并且当x(t)\in\partial\Omega\cap \mathbb{R} 时,有 x(t)=E_2x(t)=E_1.由方程(2.5),有E_2>D_2;因此,由条件(H'_2),可得

\frac{1}{T}\int^T_0g(t, E_1){\rm d}t>0, ~~ \mbox{并且} ~~\frac{1}{T}\int^T_0g(t, E_2){\rm d}t <0.

显然,我们能得到

\begin{eqnarray*}\deg\{F, \Omega\cap\mathbb{R} , 0\}&=&\deg\left\{\frac{1}{T}\int^T_0g(x){\rm d}t, \Omega\cap\mathbb{R} , 0\right\}\\ &=&\deg\{x, \Omega\cap \mathbb{R} , 0\}\neq0.\end{eqnarray*}

从而引理2.1条件(ⅲ)成立.由定理1.4可知,方程(1.4)至少有一个正的T周期解.

接下来,通过下面的例子来阐明我们的定理.

例2.1  考虑下面具有偏差变元的吸引奇性的p-Laplacian Liénard型方程

\begin{equation}{\label{eq4.1}}(\varphi_p(x'(t)))'+e^{x^5}x'(t)-\frac{1}{3}(2+\sin(4t))x^3\left(t-\frac{\sin(4t)}{5}\right)+\frac{1}{x^{\mu}}=\cos(4t), \end{equation}
(2.19)

这里p=4, \mu是一个常数且\mu\geq1.

对比方程(2.19)和方程(1.4),可知f(x)=e^{x^{5}}, g(t, x(t-\sigma(t)))=-\frac{1}{3}(2+\sin(4t))x^3(t-\frac{\sin(4t)}{5})+\frac{1}{x^{\mu}}, \sigma(t)=\frac{\sin(4t)}{5}, \sigma'(t)=\frac{4\cos(4t)}{5} < 1, T=\frac{\pi}{2}.D_2=2,显然条件(H'_2)是成立的.考虑g(t, x(t-\sigma(t)))=-\frac{1}{3}(2+\sin(4t))x^3(t-\frac{\sin(4t)}{5}))+\frac{1}{x^{\mu}},则我们可得\int^1_0\frac{1}{x^{\mu}}{\rm d}x=+\infty且有-g(t, x(t-\sigma(t)))\leq x^3+1,其中a=1, b=1.因此,条件(H'_5)和(H_6)成立.接下来,我们有下面的条件

\begin{eqnarray*}\frac{aT^{p}}{2^{p-1}}=1\times\frac{(\frac{\pi}{2})^4}{2^3}\approx0.761.\end{eqnarray*}

因此,通过定理1.4,我们得到方程(1.4)至少有一个\frac{\pi}{2}周期解.

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